4y+2=2y^2+2y+8/y

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Solution for 4y+2=2y^2+2y+8/y equation: 



4y+2=2y^2+2y+8/y

We move all terms to the left:

4y+2-(2y^2+2y+8/y)=0



Domain of the equation: y)!=0

y!=0/1

y!=0

y∈R



We get rid of parentheses

-2y^2+4y-2y-8/y+2=0

We multiply all the terms by the denominator


-2y^2*y+4y*y-2y*y+2*y-8=0

We add all the numbers together, and all the variables

-2y^2*y+2y+4y*y-2y*y-8=0

Wy multiply elements

-2y^3+4y^2-2y^2+2y-8=0

We do not support eypression: y^3

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